5[1+c]=6[2+c]

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Solution for 5[1+c]=6[2+c] equation:


Simplifying
5[1 + c] = 6[2 + c]
[1 * 5 + c * 5] = 6[2 + c]
[5 + 5c] = 6[2 + c]
5 + 5c = [2 * 6 + c * 6]
5 + 5c = [12 + 6c]

Solving
5 + 5c = 12 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
5 + 5c + -6c = 12 + 6c + -6c

Combine like terms: 5c + -6c = -1c
5 + -1c = 12 + 6c + -6c

Combine like terms: 6c + -6c = 0
5 + -1c = 12 + 0
5 + -1c = 12

Add '-5' to each side of the equation.
5 + -5 + -1c = 12 + -5

Combine like terms: 5 + -5 = 0
0 + -1c = 12 + -5
-1c = 12 + -5

Combine like terms: 12 + -5 = 7
-1c = 7

Divide each side by '-1'.
c = -7

Simplifying
c = -7

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